SOLUTION: factor completely: 2x^2-20x+50-18y^2=0

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Question 353174: factor completely:
2x^2-20x+50-18y^2=0
Found 2 solutions by CharlesG2, ewatrrr:
Answer by CharlesG2(834) (Show Source):
You can put this solution on YOUR website!
factor completely:
2x^2-20x+50-18y^2=0

this is not a quadratic equation,
quadratic equations are of form ax^2 + bx + c = 0
however let's see if it can be factored

2x^2 - 20x + 50 - 18y^2 = 0
2x^2 - 20x + 50 = 18y^2 (brought the y^2 term to other side)
x^2 - 10x + 25 = 9y^2 (divided both sides by 2)
(x - 5)(x - 5) = 3y * 3y (found square roots both sides)
(the (x-5)(x-5) does multiply with FOIL out to x^2-10x+25)
x - 5 = 3y
solving for x --> x = 3y + 5
solving for y --> -3y = -x + 5 --> 3y = x - 5 --> y = (1/3)x - 5/3

factored:
2x^2 - 20x + 50 - 18y^2 = 0
2(x^2 - 10x + 25 - 9y^2) = 0
2((x - 5)^2 - (3y)^2) = 0

Answer by ewatrrr(24785) (Show Source):
You can put this solution on YOUR website!
Hi,

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Rearrange to begin:

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factor

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