SOLUTION: f(x)=8-x^2 I got Vertex (0, x^2) Line of Symmetry x=0 Max/Min -x^2 Value of, f(0)=8 max/min I choose max. What I cannot figure out is how do I graph this one?

Algebra ->  Algebra  -> Quadratic Equations and Parabolas -> SOLUTION: f(x)=8-x^2 I got Vertex (0, x^2) Line of Symmetry x=0 Max/Min -x^2 Value of, f(0)=8 max/min I choose max. What I cannot figure out is how do I graph this one?      Log On

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Question 353035: f(x)=8-x^2
I got
Vertex (0, x^2)
Line of Symmetry x=0
Max/Min -x^2
Value of, f(0)=8 max/min
I choose max.
What I cannot figure out is how do I graph this one?
Answer by stanbon(57246) About Me  (Show Source):
You can put this solution on YOUR website!
f(x)=8-x^2
I got
Vertex ?
Vertex occurs when x = -b/(2a) = -0/(2*-1) = 0
f(0) = 8
Vertex is (0,8)
------------------------
Line of Symmetry x=0
Max/Min:: Max because the coefficient of x^2 is negative
Value of, f(0)=8 max
how do I graph this one?
Plot (0,8) and a couple points to the left and to
the right of x = 0
-------------------------
graph%28400%2C300%2C-10%2C10%2C-10%2C10%2C8-x%5E2%29
====================================
Cheers,
Stan H.