SOLUTION: f(x)=8-x^2
I got
Vertex (0, x^2)
Line of Symmetry x=0
Max/Min -x^2
Value of, f(0)=8 max/min
I choose max.
What I cannot figure out is how do I graph this one?
Algebra ->
Quadratic Equations and Parabolas
-> SOLUTION: f(x)=8-x^2
I got
Vertex (0, x^2)
Line of Symmetry x=0
Max/Min -x^2
Value of, f(0)=8 max/min
I choose max.
What I cannot figure out is how do I graph this one?
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Question 353035: f(x)=8-x^2
I got
Vertex (0, x^2)
Line of Symmetry x=0
Max/Min -x^2
Value of, f(0)=8 max/min
I choose max.
What I cannot figure out is how do I graph this one? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! f(x)=8-x^2
I got
Vertex ?
Vertex occurs when x = -b/(2a) = -0/(2*-1) = 0
f(0) = 8
Vertex is (0,8)
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Line of Symmetry x=0
Max/Min:: Max because the coefficient of x^2 is negative
Value of, f(0)=8 max
how do I graph this one?
Plot (0,8) and a couple points to the left and to
the right of x = 0
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Cheers,
Stan H.
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