SOLUTION: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function. f(x)=8-x^2

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function. f(x)=8-x^2      Log On


   

Question 349143: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function. f(x)=8-x^2
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
f%28x%29=-x%5E2%2B8
Convert to vertex form, y=a%28x-h%29%5E2%2Bk
f%28x%29=-%28x-0%29%5E2%2B8
(h,k)=(0,8)
The vertex lies on the axis of symmetry x=0.
Since the multiplier for x%5E2 is negative, the parabola opens downwards and the value at the vertex is a maximum.
ymax=8
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