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put this solution on YOUR website!x^2-6x+5=y
(x^2-6x =y-5
Complete the square on the left side and maintain the equal sign, as follows;
x^2-6x+3^2 = y-5+3^2
Factor the left side and simplify the right side to get:
(x-3)^2 = y+4
a) The vertex is (3,-4)
b) To get the x-intercept, let y=0. Then
x^2-6x+5=0
(x-5)(x-1)=0
x=5 or x=1 (these are the x-intercepts
c) To get the y-intercept, let x=0
0^2-6(0)+5=y
y=5 This is the y intercept.
d) Graph as follows:
| Solved by pluggable solver: SOLVE quadratic equation with variable |
Quadratic equation  (in our case  ) has the following solutons:
For these solutions to exist, the discriminant  should not be a negative number.
First, we need to compute the discriminant :  .
Discriminant d=16 is greater than zero. That means that there are two solutions:  .
Quadratic expression  can be factored:
Again, the answer is: 5, 1.
Here's your graph:
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