SOLUTION: Determine the nature of the solutions of the equation. x^2-14x+49=0 What does the equation have? One real solution, two non-real solutions, or two real solutions

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Determine the nature of the solutions of the equation. x^2-14x+49=0 What does the equation have? One real solution, two non-real solutions, or two real solutions      Log On


   

Question 342464: Determine the nature of the solutions of the equation.
x^2-14x+49=0
What does the equation have?
One real solution, two non-real solutions, or two real solutions
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Use the discriminant.
D=b%5E2-4ac
D=%28-14%29%5E2-4%281%29%2849%29
D=196-196
D=0
There is one real solution (a double root).
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graph%28300%2C300%2C-5%2C15%2C-10%2C10%2Cx%5E2-14x%2B49%29