Question 341559: f(x)=x^2-7x-8
What is the vertex, the line of symmetry, and the x and y intercept(s)? How do you find each one?
Thanks!
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! f(x)=x^2-7x-8
What is the vertex, the line of symmetry, and the x and y intercept(s)? How do you find each one?
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Vertex occurs at x = -b/(2a) = 7/2
f(7/2) = -20.25
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Vertex::: (3.5,-20.25)
Line of symmetry: x = 3.5
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y-int = ?
Let x = 0, then y = -8
y-int = -8
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f(x)=x^2-7x-8
x-int = ?
Let y = 0
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solve x^2-7x-8 = 0
(x-8)(x+1) = 0
x = 8 or x = -1
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x-intercepts:
x = 8 and x = -1
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Cheers,
Stan H.
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