SOLUTION: Can you help me solve
A car travels 180 mi. A second car, traveling 15 mi/hr faster than the first car, makes the same trip in 1 h less time. find the speed of each car.
Algebra ->
Quadratic Equations and Parabolas
-> SOLUTION: Can you help me solve
A car travels 180 mi. A second car, traveling 15 mi/hr faster than the first car, makes the same trip in 1 h less time. find the speed of each car.
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Question 34056: Can you help me solve
A car travels 180 mi. A second car, traveling 15 mi/hr faster than the first car, makes the same trip in 1 h less time. find the speed of each car. Found 2 solutions by tmarienatree, Paul:Answer by tmarienatree(17) (Show Source):
You can put this solution on YOUR website! i would say you would need the distance to find that and you could make a table but oher than that i dont no wat eles to say ask your teacher
The second car travels at 15+x
THe first car travels at x
Since its 1 hours less it's
d/(x)=d/(x+15)+1
and d=180
Equation:
Cross mutliply:
180[(15+x)-(x)]=(x+15)(x)
a=1, b=15, c=-2700 in quardatic formula:
simplfy:
x=45 or x=-60
remove the negative and x=45.
Hence, the speed of the first car was 45mph and the second car was 60mph.
Paul.
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