SOLUTION: If k >0 and 25x^2 + bx + 16 = (5x - k)^2 , for all values of x, what is the value of k – b? (a) -44 (b) -36 (c) 14 (d) 36 (e) 44

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: If k >0 and 25x^2 + bx + 16 = (5x - k)^2 , for all values of x, what is the value of k – b? (a) -44 (b) -36 (c) 14 (d) 36 (e) 44       Log On


   

Question 339033: If k >0 and 25x^2 + bx + 16 = (5x - k)^2 , for all values of x, what is the value of k – b?
(a) -44 (b) -36 (c) 14 (d) 36 (e) 44
Answer by galactus(183) About Me  (Show Source):
You can put this solution on YOUR website!
Since the constant in the given quadratic is 16, then k must equal 4.
If k = 4, then we have (5x-4)^2=25x^2-40x+16 and b=-40
Thus, k-b=4-(-40)=44