SOLUTION: use the quadratic formula to determine the x-intercepts (if any) of the following function. Then evaluate the function for several values of x,use the resulting points to graph the

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: use the quadratic formula to determine the x-intercepts (if any) of the following function. Then evaluate the function for several values of x,use the resulting points to graph the      Log On


   

Question 337737: use the quadratic formula to determine the x-intercepts (if any) of the following function. Then evaluate the function for several values of x,use the resulting points to graph the function. show your work.
+f%28x%29=+1%2F2x%5E2

Could someone please help me with this problem?
Thank you so much.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
use the quadratic formula to determine the x-intercepts (if any) of the following function. Then evaluate the function for several values of x,use the resulting points to graph the function. show your work.
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f(x)= (1/2)x^2
a = (1/2) ; b = 0 ; c = 0
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Formula:
x = [-b +- sqrt(b^2-4ac)]/(2a)
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x = [-0 +- sqrt(0^2-4*(1/2)*0)]/(2*(1/2))
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x = [0 +- 0]/1
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x = 0
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So the graph touches the x-axis at (0,0)
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f(x) = (1/2)x^2
Plot some points near (0,0)
If x = +1 or -1 y = (1/2)(1)^2 = 1/2
That gives you two points: (-1,1/2) and (1,1/2)
If x = 2 or -2 y = (1/2)(2^2) = 2
That gives you two points: (-2,2) and (2,2)
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graph%28400%2C300%2C-10%2C10%2C-10%2C10%2C%281%2F2%29x%5E2%29
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Cheers,
Stan H.