SOLUTION: please help solve: x^2+3x=4 and 4x^2-3x=-6 ... i do not know how to start off these problems.. help please, it is a school assignment.

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: please help solve: x^2+3x=4 and 4x^2-3x=-6 ... i do not know how to start off these problems.. help please, it is a school assignment.      Log On


   



Question 331356: please help solve: x^2+3x=4 and 4x^2-3x=-6
... i do not know how to start off these problems..
help please, it is a school assignment.

Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
x^2+3x=4
x^2+3x-4=0
(x+4)(x-1)=0
x+4=0
x=-4 ans.
x-1=0
x=1 ans.
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4x^2-3x=-6
4x^2-3x+6=0
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
X=(3+-SQRT[-3^2-4*4*6])/2*4
X=(3+-SQRT[9-96])/8
X=(3+-SQRT-87)/8
X=(3+-9.327i)/8
X=3/8+-9.327i/8
X=.375+-1.166i