SOLUTION: The length of a rectangle is 3 cm more than 2 times its width. If the area of the rectangle is 93 square centimeters, find the width of the rectangle to the nearest thousandth.
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-> SOLUTION: The length of a rectangle is 3 cm more than 2 times its width. If the area of the rectangle is 93 square centimeters, find the width of the rectangle to the nearest thousandth.
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Question 330488: The length of a rectangle is 3 cm more than 2 times its width. If the area of the rectangle is 93 square centimeters, find the width of the rectangle to the nearest thousandth.
Thank you for the service you offer Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! let width = x
length = 2x+3
..
ARea = L*W
x(2x+3)=93
2x^2+3x=93
2x^2+3x-93=0
quadratic formula
x1=(-b+sqrt(b^2-4ac))/2a
a=2, b=3, c=-93
x1=(-3+sqrt(9+744))/4
x1= 6.110 cm the width
..
x2=(-3-sqrt(9+744))/4
x2= -7.610 Ignore the negative value
