SOLUTION: How would you solve the following using the quadratic formula - showing step by step? I know the book says the answer is 2 +- sqrt(2) /2. However, I can't seem to come up with t

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: How would you solve the following using the quadratic formula - showing step by step? I know the book says the answer is 2 +- sqrt(2) /2. However, I can't seem to come up with t      Log On


   

Question 32754: How would you solve the following using the quadratic formula - showing step by step? I know the book says the answer is 2 +- sqrt(2) /2.
However, I can't seem to come up with that. Here is the problem:
(3y-1)(2y-3)=y
Here's what I have so far:
+6y%5E2-11y%2B3+=+y+
+6y%5E2-12y%2B3+=+0+
= -(-12) +- sqrt((-12)^2 -4(6)(3) / 2(6)
= 12 +- sqrt(144-72) / 12
= 12 +- sqrt(72) / 12
= 12+- sqrt(36 *2) / 12
= 12 +- 6 sqrt(2) / 12
then what would follow? Thank you.
Answer by mukhopadhyay(490) About Me  (Show Source):
You can put this solution on YOUR website!
= [12 +- 6 sqrt(2)] / 12
= 1 +- Sqrt(2)/12
The roots of the equation are: 1 + sqrt(2)/12 and 1 - sqrt(2)/12