SOLUTION: The flower garden has the shape of a right traingle. 51 ft. of a perennial border forms the hypotenuse of the traingle, and one leg is 21 ft. longer than the other leg. Find the le
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-> SOLUTION: The flower garden has the shape of a right traingle. 51 ft. of a perennial border forms the hypotenuse of the traingle, and one leg is 21 ft. longer than the other leg. Find the le
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Question 325806: The flower garden has the shape of a right traingle. 51 ft. of a perennial border forms the hypotenuse of the traingle, and one leg is 21 ft. longer than the other leg. Find the lengths of the legs. What are the lengths of the legs in ft? Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! X^2+(X+21)^2=51^2
X^2+X^2+42X+441=2,601
2X^2+42X+441-2,601=0
2X^2+42X-2,160=0
2(X^2+21X-1,080)=0
2(X-24)(X+45)=0
X-24=0
X=24 ANS.
X+45=0
X=-45 ANS.
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