# SOLUTION: The sum of the squares of two consecutive integers is 613. What are the integers? Let x be one integer. Therefore x +1 is the next integer. x^2+(x+1)^2=613

Algebra ->  Algebra  -> Quadratic Equations and Parabolas -> SOLUTION: The sum of the squares of two consecutive integers is 613. What are the integers? Let x be one integer. Therefore x +1 is the next integer. x^2+(x+1)^2=613      Log On

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 Question 324085: The sum of the squares of two consecutive integers is 613. What are the integers? Let x be one integer. Therefore x +1 is the next integer. x^2+(x+1)^2=613Answer by Fombitz(13828)   (Show Source): You can put this solution on YOUR website! Complete the square. and . . . The integers are either -18 and -17 or 17 and 18.