SOLUTION: For each quadratic function, state: direction of opening, vertex, equation of axis of symmetry, coordinates of maximum or minimum and domain and range. y=3(x-4)^2+1

Algebra ->  Algebra  -> Quadratic Equations and Parabolas -> SOLUTION: For each quadratic function, state: direction of opening, vertex, equation of axis of symmetry, coordinates of maximum or minimum and domain and range. y=3(x-4)^2+1      Log On

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Question 322172: For each quadratic function, state: direction of opening, vertex, equation of axis of symmetry, coordinates of maximum or minimum and domain and range.
y=3(x-4)^2+1
Answer by Fombitz(13828) About Me  (Show Source):
You can put this solution on YOUR website!
The equation is in vertex form, y=a%28x-h%29%5E2%2Bk where (h,k) is the vertex.
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Direction of opening: Upwards, the coefficient of x%5E2 term (3) is positive.
Vertex: (4,1)
The axis of symmetry contains the vertex:x=4
Minimum occurs at the vertex:ymin=1
Domain: (-infinity,infinity)
Range: (1,infinity)
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