SOLUTION: A circular pool measures 16 feet across. One cubic yard of concrete is to be used to create a circular border with uniform width around the pool. The border is to have a depth of 2

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Question 315664: A circular pool measures 16 feet across. One cubic yard of concrete is to be used to create a circular border with uniform width around the pool. The border is to have a depth of 2 inches, how wide will the border be? (1 cubic yard=36 cubic feet)
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
A circular pool measures 16 feet across.
One cubic yard of concrete is to be used to create a circular border with uniform width around the pool.
The border is to have a depth of 2 inches, how wide will the border be?
(1 cubic yard=36 cubic feet)
I think there is 27 cu/ft in a cubic yard, but will do the problem using 36
:
Let x = the width of the concrete border
:
From the given information we know the area of the concrete border will be:
2 in = 2/12 = 1%2F6 ft
A = 36%2F%281%2F6%29 = 216 sq/ft is the area of the concrete
:
Radius of the pool = 8 ft
Radius overall, including the circular concrete border = (x+8)
:
Area of pool:
A = pi%2A8%5E2
A = 201 sq/ft
:
Equation for total area
pi%2A%28x%2B8%29%5E2 = 201 + 216
:
pi%2A%28x%5E2+%2B+16x+%2B+64%29 = 417
:
x^2 + 16x + 64 = 417%2Fpi
:
x^2 + 16x + 64 = 132.74
:
x^2 + 16x + 64 - 132.74 = 0
:
x^2 + 16x - 68.74 = 0
Use the quadratic equation
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
In this equation, a=1, b=16, c=-68.74
x+=+%28-16+%2B-+sqrt%2816%5E2-4%2A1%2A-68.74+%29%29%2F%282%2A1%29+
:
x+=+%28-16+%2B-+sqrt%28256+-%28-275%29+%29%29%2F2+
:
x+=+%28-16+%2B-+sqrt%28531%29%29%2F2+
Positive solution is all we want here
x+=+%28-16+%2B+23%29%2F2+
x = 7%2F2
x = 3.5 ft is the width of the concrete
:
:
Check solution by finding the total area, then subtract the pool area
r = 8 + 3.5 = 11.5
A = pi%2A11.5%5E2
A = 415.5
415.5 - 201 = 214.5 area of concrete
then
214.5 * 1%2F6 = 35.7 ~ 36 cu/ft of concrete