# SOLUTION: Hi, I'm trying to find all real solutions to this equation: 4x^-4-16x^-2+4=0 I have: 4/x^4-16/x^2+4=0 multiplying by x^4: 4-16x^2+4=0 4x^4-16x^2+4=0 4(x^4-4x^2+1) = 0 (

Algebra ->  Algebra  -> Quadratic Equations and Parabolas -> SOLUTION: Hi, I'm trying to find all real solutions to this equation: 4x^-4-16x^-2+4=0 I have: 4/x^4-16/x^2+4=0 multiplying by x^4: 4-16x^2+4=0 4x^4-16x^2+4=0 4(x^4-4x^2+1) = 0 (      Log On

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 Question 31323This question is from textbook College Algebra : Hi, I'm trying to find all real solutions to this equation: 4x^-4-16x^-2+4=0 I have: 4/x^4-16/x^2+4=0 multiplying by x^4: 4-16x^2+4=0 4x^4-16x^2+4=0 4(x^4-4x^2+1) = 0 (unfactorable?) a=1;b=4;c=1 Using the quadratic equation I get: -4+-sq root of 3, but this doesn't seem right. Thanks for all your help!This question is from textbook College Algebra Answer by longjonsilver(2297)   (Show Source): You can put this solution on YOUR website!you had an error with your signs half way through... this doesn't factorise simply. So lets use the quadratic formula. First however, let --> so, so, or Hence, from , we get: or or jon.