SOLUTION: How do you solve the quadratic equation 3x^2-7x+2=0 using formula? I have worked it out the overall square root to -73 however when i type this is my calculator says maths error?

You can put this solution on YOUR website!


You have two difficulties here.
First is the fact that you are trying to take the square root of a negative number. Remember, is not defined in the real numbers -- no wonder your calculator is pitching a fit! In order to find an approximation of the square root of -73 you need to factor it into two parts, (-1)(73). Use the definition of the imaginary number , that is , to write

But that problem is secondary to the fact that you improperly calculated the value under the radical in the quadratic formula.



For this equation, , , and







Note: -7 times -7 is +49.





or




John

You can put this solution on YOUR website!
"How do you solve the quadratic equation 3x^2-7x+2=0 using formula?
I have worked it out the overall square root to -73 however when i type this is my calculator says maths error?
Thanks For Your Help"

a = 3, b = -7, c = 2




x1 = (7 + 5)/6 = 12/6 = 2
x2 = (7 - 5)/6 = 2/6 = 1/3
check:
(x - 2)(x - 1/3) = 0 (use FOIL)
x^2 -(1/3)x -2x + 2/3 = 0
3x^2 - x - 6x + 2 = 0 (multiplied both sides by 3)
3x^2 - 7x + 2 = 0
not sure how you got your answer,
but if you taking a square root of a negative number on a calculator
you are going to get an error