SOLUTION: The equation is: y = 1x2+4x+3
The parabola graph puts it as: x= -1, -3.
The equation didn't have negative numbers in it in the first place. So why does the graph make them ne
Algebra ->
Quadratic Equations and Parabolas
-> SOLUTION: The equation is: y = 1x2+4x+3
The parabola graph puts it as: x= -1, -3.
The equation didn't have negative numbers in it in the first place. So why does the graph make them ne
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Question 310072: The equation is: y = 1x2+4x+3
The parabola graph puts it as: x= -1, -3.
The equation didn't have negative numbers in it in the first place. So why does the graph make them negatives? Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! y = x2+4x+3
The parabola graph puts it as: x= -1, -3.
The equation didn't have negative numbers in it in the first place. So why does the graph make them negatives?
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Find where y = 0:
(x+3)*(x+1) = 0
For the product to be 0, either x+3 = 0 or x+1 = 0
x+3 = 0
x = -3
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x+1 = 0
x = -1
