SOLUTION: N(x)=0.4x^2+8.8x+11 x=days Peak sales of tickets will be on what day and how many tickets are sold that day?

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: N(x)=0.4x^2+8.8x+11 x=days Peak sales of tickets will be on what day and how many tickets are sold that day?      Log On


   

Question 309682: N(x)=0.4x^2+8.8x+11
x=days
Peak sales of tickets will be on what day and how many tickets are sold that day?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
N(x)=-0.4x^2+8.8x+11 (coefficient of x^2 has to be negative)
x=days
Peak sales of tickets will be on what day and how many tickets are sold that day?
:
This is a quadratic equation, find the axis of symmetry to find the day of max sales
Use the formula: x = -b/(2a), in this equation a=-.4, b=8.8
x = %28-8.8%29%2F%282%2A-.4%29
x = %28-8.8%29%2F%28-.8%29
x = +11th day will be peak sales
:
Find the no. of sales on that day
N(x) = -0.4x^2 + 8.8x + 11
Replace x with 11
N(11) = -0.4(11^2) + 8.8(11) + 11
N(11) = -0.4(121) + 96.8 + 11
N(11) = -48.4 + 96.8 + 11
N(11) = 59.4 ~ 59 tickets sold on the 11th day