SOLUTION: Question: The area of a rectangle is 4m^2 and its length is 3m longer that its width. Find the dimensions of the rectangle.

Algebra ->  Algebra  -> Quadratic Equations and Parabolas -> SOLUTION: Question: The area of a rectangle is 4m^2 and its length is 3m longer that its width. Find the dimensions of the rectangle.      Log On

Ad: You enter your algebra equation or inequality - Algebrator solves it step-by-step while providing clear explanations. Free on-line demo .
Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!
Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

   

Question 30795: Question:
The area of a rectangle is 4m^2 and its length is 3m longer that its width. Find the dimensions of the rectangle.
Answer by troyapplehelen(46) About Me  (Show Source):
You can put this solution on YOUR website!
A=w.l
4=x.(x+3)
0=x^2+3x-4
=(x-1)(x+4) x= 1 or -4, h/w, there is no such - number of length. so,
x, which is width, is 1 and its length is 4(=1+3).
The Answer width is 1 m, length is 4 m.