SOLUTION: find two consecutive intergers such that the square of the smaller plus twice the larger is 50

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Question 305374: find two consecutive intergers such that the square of the smaller plus twice the larger is 50
Answer by Fombitz(32388) About Me  (Show Source):
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N - first integer (smaller)
N%2B1 - next consecutive integer (larger)
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N%5E2%2B2%28N%2B1%29=50
N%5E2%2B2N%2B2=50
N%5E2%2B2N-48=0
%28N%2B8%29%28N-6%29=0
Two solutions:
N%2B8=0
N=-8
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N-6=0
N=6
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The two integers are either (-8,-7) or (6,7).