SOLUTION: How do you find the domain and range of a quadratic equation??? And if I were to get a complex root from -40+/-the square root of negative 1472 all over 32. Would my X= -40+/- 8the

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: How do you find the domain and range of a quadratic equation??? And if I were to get a complex root from -40+/-the square root of negative 1472 all over 32. Would my X= -40+/- 8the      Log On


   

Question 3010: How do you find the domain and range of a quadratic equation??? And if I were to get a complex root from -40+/-the square root of negative 1472 all over 32. Would my X= -40+/- 8the square root of 23i all over 32? And if so, what are the steps to getting there???
Answer by longjonsilver(2297) About Me  (Show Source):
You can put this solution on YOUR website!
domain is basically all the valid numbers you can put into an equation without it breaking...the x-values

range is that set of number you get out of the equation if you put all the values of the domain into it...the y-values.

%28-40+%2B-+sqrt%28-1472%29%29%2F32
%28-40+%2B-+sqrt%281472%2A%28-1%29%29%29%2F32
%28-40+%2B-+sqrt%281472%29sqrt%28-1%29%29%2F32
%28-40+%2B-+sqrt%281472%29i%29%2F32

Now to simplify the 1472...2*736....4*368... 16*92... 64*23...we have a square root, so look for a number that will have a nice root, like 4, 9, 16, 25, 36, 49, 64 etc

so sqrt%281472%29 can be written as sqrt%2864%2A23%29 which is sqrt%2864%29sqrt%2823%29 which is 8sqrt%2823%29

So, our calculation now becomes: %28-40+%2B-+8sqrt%2823%29i%29%2F32 which is what you said, and this can simplify a little further to %28-8%285+%2B-+sqrt%2823%29i%29%29%2F32 which is %28-5+%2B-+sqrt%2823%29i%29%2F4
jon