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put this solution on YOUR website!One solution of 3x^2-7x+c=0 is 1/3.
LET THE OTHER ROOT BE A...IN A QUADRATIC EQN.AX^2+BX+C=0..SUM OF ROOTS =-B/A AND PRODUCT OF ROOTS = C/A...HENCE.....
SUM OF ROOTS =A+1/3=-(-7)/3=7/3....SO A=7/3-1/3=6/3=2
PRODUCT OF ROOTS =A*1/3=2*1/3=2/3=C/3....SO C=2