SOLUTION: The height of a curved support beam can be modeled by f(x)=(-x^2)/300+12. Find the height and width of the beam.

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: The height of a curved support beam can be modeled by f(x)=(-x^2)/300+12. Find the height and width of the beam.       Log On


   

Question 296879: The height of a curved support beam can be modeled by f(x)=(-x^2)/300+12. Find the height and width of the beam.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
The height of a curved support beam can be modeled by f(x)=(-x^2)/300+12.
Find the height and width of the beam.
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What does it look like?
graph%28400%2C300%2C-75%2C75%2C-10%2C15%2C%28-x%5E2%29%2F300+%2B+12%29
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Height?
Vertex occurs when x = -b/(2a) = 0/(-2(1/300)) = 0
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The height is f(0) = 12 ft.
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Width?
Find the x-intercepts.
Solve (-x^2/300) + 12 = 0
x^2/300 = 12
x^2 = 3600
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x = 60 or x = -60
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Width = 2(60) = 120 ft.
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Cheers,
Stan H.