SOLUTION: Solve for z, where z is a real number √(4z+12) = z

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Question 293809: Solve for z, where z is a real number
√(4z+12) = z
Answer by user_dude2008(1862) About Me  (Show Source):
You can put this solution on YOUR website!
√(4z+12) = z

4z+12 = z^2


z^2-4z-12=0

(z-6)(z+2)=0

z=6 or z=-2

only answer is z=6