SOLUTION: 16x^2-8x+1=0

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Question 285233: 16x^2-8x+1=0
Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
16x%5E2-8x%2B1=0
One side is already zero. So we factor it:
%284x-1%29%5E2+=+0
And by the Zero Product Property we know that this factor must be zero:
4x - 1 = 0
Solving this we get
x = 1/4