SOLUTION: Solve using the five-step problem-solving process. Show all steps necessary to arrive at your solution. The product of two consecutive positive integers is 272. Find the intege

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Question 282422: Solve using the five-step problem-solving process. Show all steps necessary to arrive at your solution.
The product of two consecutive positive integers is 272. Find the integers.

Found 2 solutions by richwmiller, solver91311:
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
x*(x+1)=272
x^2+x-272=0
16 and 17
Solved by pluggable solver: Factoring using the AC method (Factor by Grouping)


Looking at the expression x%5E2%2Bx-272, we can see that the first coefficient is 1, the second coefficient is 1, and the last term is -272.



Now multiply the first coefficient 1 by the last term -272 to get %281%29%28-272%29=-272.



Now the question is: what two whole numbers multiply to -272 (the previous product) and add to the second coefficient 1?



To find these two numbers, we need to list all of the factors of -272 (the previous product).



Factors of -272:

1,2,4,8,16,17,34,68,136,272

-1,-2,-4,-8,-16,-17,-34,-68,-136,-272



Note: list the negative of each factor. This will allow us to find all possible combinations.



These factors pair up and multiply to -272.

1*(-272) = -272
2*(-136) = -272
4*(-68) = -272
8*(-34) = -272
16*(-17) = -272
(-1)*(272) = -272
(-2)*(136) = -272
(-4)*(68) = -272
(-8)*(34) = -272
(-16)*(17) = -272


Now let's add up each pair of factors to see if one pair adds to the middle coefficient 1:



First NumberSecond NumberSum
1-2721+(-272)=-271
2-1362+(-136)=-134
4-684+(-68)=-64
8-348+(-34)=-26
16-1716+(-17)=-1
-1272-1+272=271
-2136-2+136=134
-468-4+68=64
-834-8+34=26
-1617-16+17=1




From the table, we can see that the two numbers -16 and 17 add to 1 (the middle coefficient).



So the two numbers -16 and 17 both multiply to -272 and add to 1



Now replace the middle term 1x with -16x%2B17x. Remember, -16 and 17 add to 1. So this shows us that -16x%2B17x=1x.



x%5E2%2Bhighlight%28-16x%2B17x%29-272 Replace the second term 1x with -16x%2B17x.



%28x%5E2-16x%29%2B%2817x-272%29 Group the terms into two pairs.



x%28x-16%29%2B%2817x-272%29 Factor out the GCF x from the first group.



x%28x-16%29%2B17%28x-16%29 Factor out 17 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.



%28x%2B17%29%28x-16%29 Combine like terms. Or factor out the common term x-16



===============================================================



Answer:



So x%5E2%2Bx-272 factors to %28x%2B17%29%28x-16%29.



In other words, x%5E2%2Bx-272=%28x%2B17%29%28x-16%29.



Note: you can check the answer by expanding %28x%2B17%29%28x-16%29 to get x%5E2%2Bx-272 or by graphing the original expression and the answer (the two graphs should be identical).


Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 1x%5E2%2B1x%2B-272+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%281%29%5E2-4%2A1%2A-272=1089.

Discriminant d=1089 is greater than zero. That means that there are two solutions: +x%5B12%5D+=+%28-1%2B-sqrt%28+1089+%29%29%2F2%5Ca.

x%5B1%5D+=+%28-%281%29%2Bsqrt%28+1089+%29%29%2F2%5C1+=+16
x%5B2%5D+=+%28-%281%29-sqrt%28+1089+%29%29%2F2%5C1+=+-17

Quadratic expression 1x%5E2%2B1x%2B-272 can be factored:
1x%5E2%2B1x%2B-272+=+1%28x-16%29%2A%28x--17%29
Again, the answer is: 16, -17. Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B1%2Ax%2B-272+%29

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Let represent the first of two consecutive positive integers. Then the next consecutive positive integer must be

The product of these two integers is then

This product is equal to 272, so:



Just put the equation in standard form, factor, and solve. Exclude the negative root because the question asks for positive integers.

John