SOLUTION: -16x^2-4x+4=0 What is the value of the discriminant?

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Question 282052: -16x^2-4x+4=0
What is the value of the discriminant?
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
From -16x%5E2-4x%2B4 we can see that a=-16, b=-4, and c=4


D=b%5E2-4ac Start with the discriminant formula.


D=%28-4%29%5E2-4%28-16%29%284%29 Plug in a=-16, b=-4, and c=4


D=16-4%28-16%29%284%29 Square -4 to get 16


D=16--256 Multiply 4%28-16%29%284%29 to get %28-64%29%284%29=-256


D=16%2B256 Rewrite D=16--256 as D=16%2B256


D=272 Add 16 to 256 to get 272


So the discriminant of -16x%5E2-4x%2B4 is 272.


Since the discriminant is greater than zero, this means that there are two real solutions.