SOLUTION: solve using the quadriatic formula. im not sure how to go about this. please help if possible thanks 5x^2-3x-3=0

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Question 279662: solve using the quadriatic formula. im not sure how to go about this. please help if possible thanks 5x^2-3x-3=0
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: Quadratic Formula
Let's use the quadratic formula to solve for x:


Starting with the general quadratic


ax%5E2%2Bbx%2Bc=0


the general solution using the quadratic equation is:


x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29




So lets solve 5%2Ax%5E2-3%2Ax-3=0 ( notice a=5, b=-3, and c=-3)





x+=+%28--3+%2B-+sqrt%28+%28-3%29%5E2-4%2A5%2A-3+%29%29%2F%282%2A5%29 Plug in a=5, b=-3, and c=-3




x+=+%283+%2B-+sqrt%28+%28-3%29%5E2-4%2A5%2A-3+%29%29%2F%282%2A5%29 Negate -3 to get 3




x+=+%283+%2B-+sqrt%28+9-4%2A5%2A-3+%29%29%2F%282%2A5%29 Square -3 to get 9 (note: remember when you square -3, you must square the negative as well. This is because %28-3%29%5E2=-3%2A-3=9.)




x+=+%283+%2B-+sqrt%28+9%2B60+%29%29%2F%282%2A5%29 Multiply -4%2A-3%2A5 to get 60




x+=+%283+%2B-+sqrt%28+69+%29%29%2F%282%2A5%29 Combine like terms in the radicand (everything under the square root)




x+=+%283+%2B-+sqrt%2869%29%29%2F%282%2A5%29 Simplify the square root (note: If you need help with simplifying the square root, check out this solver)




x+=+%283+%2B-+sqrt%2869%29%29%2F10 Multiply 2 and 5 to get 10


So now the expression breaks down into two parts


x+=+%283+%2B+sqrt%2869%29%29%2F10 or x+=+%283+-+sqrt%2869%29%29%2F10



Now break up the fraction



x=%2B3%2F10%2Bsqrt%2869%29%2F10 or x=%2B3%2F10-sqrt%2869%29%2F10



Simplify



x=3%2F10%2Bsqrt%2869%29%2F10 or x=3%2F10-sqrt%2869%29%2F10



So the solutions are:

x=3%2F10%2Bsqrt%2869%29%2F10 or x=3%2F10-sqrt%2869%29%2F10