# SOLUTION: If an object is given an initial velocity of v0 feet per second from a height of S0 feet, then its height S after t seconds is given by the formula S = -16t2 +v0t + S0. A rock is

Algebra ->  Algebra  -> Quadratic Equations and Parabolas -> SOLUTION: If an object is given an initial velocity of v0 feet per second from a height of S0 feet, then its height S after t seconds is given by the formula S = -16t2 +v0t + S0. A rock is      Log On

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Question 278774: If an object is given an initial velocity of v0 feet per second from a height of S0 feet, then its height S after t seconds is given by the formula S = -16t2 +v0t + S0. A rock is thrown into the air at 26 feet per second from a height of 13 feet. How long does it take to reach the earth?
Answer by vleith(2825)   (Show Source):
You can put this solution on YOUR website!

A rock is thrown into the air at 26 feet per second from a height of 13 feet.
So S0 = 13 and V0= 26. The height when it hits the ground is 0

Use the quadratic equation to solve
 Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc) Quadratic equation (in our case ) has the following solutons: For these solutions to exist, the discriminant should not be a negative number. First, we need to compute the discriminant : . Discriminant d=1508 is greater than zero. That means that there are two solutions: . Quadratic expression can be factored: Again, the answer is: -0.401030489934225, 2.02603048993423. Here's your graph: