You can put this solution on YOUR website! the vertex of y = 3x^2 + x - 2 is found by using the formula for the min/max point of the quadratic equation.
that formula is x = -b/2a.
the standard form of the quadratic equation is ax^2 + bx + c where a is the coefficient of the x^2 term and b is the coefficient of the x term and c is the constant term.
in your equation of 3x^2 + x - 2:
a = 3
b = 1
c = -2
in the formula of x = -b/2a, you get:
x = -1/6 which is equal to -.166666667
since x = -1/6 and f(x) = y = 3x^2 + x - 2, then f(-1/6) = 3*(-1/6)^2 + (-1/6) - 2.
solve for f(-1/6) and you get y = -75/36 which is equal to -2.0833333333.
the vertex should be at (x,y) = ((-1/6),(-75/36))
a graph of the equation of 3x^2 + x - 2 is shown below:
a horizontal line was added at y = -75/36 in the graph to show you more clearly the y value of the vertex.
