SOLUTION: All of these need to be factored, please show your work. Because I don't understand how to do it. 112v ^3+ 34v ^2 - 6v 90s^2-195sw+100w ^2 p^2(x-r)-64(x-r)

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: All of these need to be factored, please show your work. Because I don't understand how to do it. 112v ^3+ 34v ^2 - 6v 90s^2-195sw+100w ^2 p^2(x-r)-64(x-r)      Log On


   

Question 277230: All of these need to be factored, please show your work. Because I don't understand how to do it.
112v ^3+ 34v ^2 - 6v
90s^2-195sw+100w ^2
p^2(x-r)-64(x-r)
Answer by JBarnum(2146) About Me  (Show Source):
You can put this solution on YOUR website!
112v%5E3%2B34v%5E2-6v first find what is in common with all 3 variables, each one has atleast 1v and can be divided by a 2 evenly. so if we factor 2v out it should look like this:
2v%2856v%5E2%2B17v-3%29 i would split the 17v into 14v+3v
2v%2856v%5E2%2B14v%2B3v-3%29 no u can group them
2v%2856v%5E2%2B14v%29%2B2v%283v-3%29 factor out a 14 and 1v in the first group and a 3 in the second group
28v%5E2%284v%2B1%29%2B6v%28v-1%29 thats as factored as i can get it


90s%5E2-195sw%2B100w%5E2 highest divisable number is 5 that i can see at first glance so i will factor out a 5
5%2818s%5E2-39sw%2B20w%5E2%29 i would split the -39sw to -9sw+(-30sw)
5%2818s%5E2-9sw%2B%28-30sw%29%2B20w%5E2%29 now u can split the 2
5%2818s%5E2-9sw%29%2B5%28-30sw%2B20w%5E2%29
5%2818s%5E2-9sw%29%2B5%28-30sw%2B20w%5E2%29 in the first group a 9 and 1s can be factores out, in the second group a 10 and 1w can be factored out
45s%282s-9w%29%2B50w%28-3s%2B2w%29 thats the most i can factor it


p%5E2%28x-r%29-64%28x-r%29 facter the (x-r)out
%28x-r%29%28p%5E2-64%29 theres a perfect squre left behind so factor it out
%28x-r%29%28%28p-8%29%28p%2B8%29%29