SOLUTION: Area of a painting. A rectangular painting with a width of x centimeters has an area of x^2 +50x square centimeters. Find a binomial that represents the length.

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Area of a painting. A rectangular painting with a width of x centimeters has an area of x^2 +50x square centimeters. Find a binomial that represents the length.       Log On


   

Question 271699: Area of a painting. A rectangular painting with a width of x centimeters has an area of x^2 +50x square centimeters. Find a binomial that represents the length.
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
Let y=length
x*y=x^2+50x
x*y=x*(x+50)
y=50+x
Length equals 50+x