SOLUTION: Please help me solve using completing the square: {{{ t^2-8t+40=0 }}}

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Question 269827: Please help me solve using completing the square: +t%5E2-8t%2B40=0+
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Solve by completing the square:
t%5E2-8t%2B40+=+0 Subtract 40 from both sides.
t%5E2-8t+=+-40 Now add the square of half the coefficient of the t-term to both sides. This is %28-8%2F2%29%5E2+=+16
t%5E2-8t%2B16+=+-40%2B16 Simplify.
%28t-4%29%5E2+=+-24 Take the square root of both sides.
t-4+=+sqrt%28-24%29 or t-4+=+-sqrt%28-24%29 Add 4 to both sides of each solution.
t+=+4%2Bsqrt%28-24%29 or t+=+4-sqrt%28-24%29 This could be further simplified to:
t+=+4%2B2sqrt%28-6%29 or t+=+4-2sqrt%28-6%29