Question 267876: how do you get the quotient for -9/i in the form a + bi
and
how do you get the quotient for
9+3i
_____
4 -8i Found 3 solutions by stanbon, Alan3354, josmiceli:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! how do you get the quotient for
-9/i in the form a + bi
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Multiply numerator and denominator by "i" to get:
-9i/(-1)
= 9i
= 0+9i
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and
how do you get the quotient for
(9+3i)/(4 -8i)
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Multiply numerator and denominator by 4+8i to get:
[(4+8i)(9+3i)]/[16+64]
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= [36-24+72i+12i]/80
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= [12+84i]/80
Reduce to get:
= [3 + 21i]/20
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Cheers,
Stan H.
You can put this solution on YOUR website! how do you get the quotient for -9/i in the form a + bi
Multiply NUM and DEN by i
= -9i/i^2
= 9i
It is in a + bi form, a = 0
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how do you get the quotient for
9+3i
_____
4 -8i
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Multiply NUM and DEN by the conjugate of the DEN 4+8i
= (9+3i)*(4+8i)/(16+64)
= (12 + 84i)/80
= (3+21i)/20
or (3/20)*(1+7i)
(