SOLUTION: Please help me solve this equation: 6x^2-13x-8=0

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Question 263607: Please help me solve this equation: 6x^2-13x-8=0

Found 2 solutions by stanbon, richwmiller:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Please help me solve this equation:
6x^2-13x-8=0
Factor:
6x^2 - 16x + 3x - 8 = 0
2x(3x-8) + (3x-8) = 0
(3x-8)(2x+1) = 0
x = 8/3 or x = -1/2
=============================
Cheers,
Stan H.

Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
6x^2-13x-8=0
(2x+1)(3x-8) = 0
how to factor
Solved by pluggable solver: Factoring using the AC method (Factor by Grouping)


Looking at the expression 6x%5E2-13x-8, we can see that the first coefficient is 6, the second coefficient is -13, and the last term is -8.



Now multiply the first coefficient 6 by the last term -8 to get %286%29%28-8%29=-48.



Now the question is: what two whole numbers multiply to -48 (the previous product) and add to the second coefficient -13?



To find these two numbers, we need to list all of the factors of -48 (the previous product).



Factors of -48:

1,2,3,4,6,8,12,16,24,48

-1,-2,-3,-4,-6,-8,-12,-16,-24,-48



Note: list the negative of each factor. This will allow us to find all possible combinations.



These factors pair up and multiply to -48.

1*(-48) = -48
2*(-24) = -48
3*(-16) = -48
4*(-12) = -48
6*(-8) = -48
(-1)*(48) = -48
(-2)*(24) = -48
(-3)*(16) = -48
(-4)*(12) = -48
(-6)*(8) = -48


Now let's add up each pair of factors to see if one pair adds to the middle coefficient -13:



First NumberSecond NumberSum
1-481+(-48)=-47
2-242+(-24)=-22
3-163+(-16)=-13
4-124+(-12)=-8
6-86+(-8)=-2
-148-1+48=47
-224-2+24=22
-316-3+16=13
-412-4+12=8
-68-6+8=2




From the table, we can see that the two numbers 3 and -16 add to -13 (the middle coefficient).



So the two numbers 3 and -16 both multiply to -48 and add to -13



Now replace the middle term -13x with 3x-16x. Remember, 3 and -16 add to -13. So this shows us that 3x-16x=-13x.



6x%5E2%2Bhighlight%283x-16x%29-8 Replace the second term -13x with 3x-16x.



%286x%5E2%2B3x%29%2B%28-16x-8%29 Group the terms into two pairs.



3x%282x%2B1%29%2B%28-16x-8%29 Factor out the GCF 3x from the first group.



3x%282x%2B1%29-8%282x%2B1%29 Factor out 8 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.



%283x-8%29%282x%2B1%29 Combine like terms. Or factor out the common term 2x%2B1



===============================================================



Answer:



So 6%2Ax%5E2-13%2Ax-8 factors to %283x-8%29%282x%2B1%29.



In other words, 6%2Ax%5E2-13%2Ax-8=%283x-8%29%282x%2B1%29.



Note: you can check the answer by expanding %283x-8%29%282x%2B1%29 to get 6%2Ax%5E2-13%2Ax-8 or by graphing the original expression and the answer (the two graphs should be identical).


solve the quadratic
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 6x%5E2%2B-13x%2B-8+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%28-13%29%5E2-4%2A6%2A-8=361.

Discriminant d=361 is greater than zero. That means that there are two solutions: +x%5B12%5D+=+%28--13%2B-sqrt%28+361+%29%29%2F2%5Ca.

x%5B1%5D+=+%28-%28-13%29%2Bsqrt%28+361+%29%29%2F2%5C6+=+2.66666666666667
x%5B2%5D+=+%28-%28-13%29-sqrt%28+361+%29%29%2F2%5C6+=+-0.5

Quadratic expression 6x%5E2%2B-13x%2B-8 can be factored:
6x%5E2%2B-13x%2B-8+=+6%28x-2.66666666666667%29%2A%28x--0.5%29
Again, the answer is: 2.66666666666667, -0.5. Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+6%2Ax%5E2%2B-13%2Ax%2B-8+%29