SOLUTION: The length of a rectangle is twice the width. The area is 98yd^2. Find the length and the width.
The length is ? yd.
(Simplify your answer)
The width is ? yd.
(Simplify y
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-> SOLUTION: The length of a rectangle is twice the width. The area is 98yd^2. Find the length and the width.
The length is ? yd.
(Simplify your answer)
The width is ? yd.
(Simplify y
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Question 258645: The length of a rectangle is twice the width. The area is 98yd^2. Find the length and the width.
The length is ? yd.
(Simplify your answer)
The width is ? yd.
(Simplify your answer)
Thank you very much for your help with this problem. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! The length of a rectangle is twice the width. The area is 98yd^2. Find the length and the width.
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L = 2W
Area = LW
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98 = (2W)W
49 = w^2
W = 7 yds (width)
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L = 2W = 14 yds (length)
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Cheers,
Stan H.
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The length is ? yd.
(Simplify your answer)
The width is ? yd.
(