Question 258528: Please Help Me Solve This Quadratic Equation Application:
The Border of uniform width around a pool has outer dimensions of 26 feet by 66 feet. Find the width of the border if the pool has an area of 1200 square feet
Answer by checkley77(12844)   (Show Source):
You can put this solution on YOUR website! (26-2x)(66-2x)=1,200
1,716-132x-52x+4x^2=1,200
4x^2-184x+1,716-1,200=0
4x^2-184x+516=0
4(x^2-46x+129)=0
4(x-43)(x-3)=0
x-3=0
x=3 ft. is the width of the border around the pool.
Proof:
(26-2*3)(66-2*3)=1,200
(26-6)(66-6)=1,200
20*60=1,200
1,200=1,200
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