SOLUTION: What do I do when i get to: x= 8 +/- 6 the square root of 3 all divided by 2 the original question was {{{ x^2-8x-11=0 }}}

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Question 254002: What do I do when i get to:
x= 8 +/- 6 the square root of 3 all divided by 2
the original question was +x%5E2-8x-11=0+
Answer by drk(1908) About Me  (Show Source):
You can put this solution on YOUR website!
We have this:
+x%5E2-8x-11=0+
If we apply quadratic, we get
x+=+%288+%2B-+sqrt%28+64-4%2A1%2A%28-11%29%29%29%2F%282%29+
and then
%288+%2B-+sqrt%28108%29%29+%2F++2
and finally
x+=+%288+%2B-+6sqrt%283+%29%29%2F%282%29+
divide every outside number by 2 to get
x+=+4+%2B-+3sqrt%283%29