Question 253261: Tim kicks a ball off the ground. After t seconds, its height, h (in feet), is given by the formula h + -16t^2 + 64t. What is the maximum height reached by the ball? Answer by Greenfinch(383) (Show Source):
You can put this solution on YOUR website! Assuming the formula is h = 16t^2 +64t the maximum height will occur
when dt/dh = 0.
so 32t +64 = 0 gives t = 2
At t = 2, h = 64 which is maximum height