SOLUTION: If x^2 −3x − 21 = y and x^2 − 4x −18 = y , what is the product of (x − 5)(x − 7)(x + 2)(x + 3) in terms of y?

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: If x^2 −3x − 21 = y and x^2 − 4x −18 = y , what is the product of (x − 5)(x − 7)(x + 2)(x + 3) in terms of y?      Log On


   

Question 252554: If x^2 −3x − 21 = y and x^2 − 4x −18 = y , what is the product of
(x − 5)(x − 7)(x + 2)(x + 3) in terms of y?
Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2-3x-21+=+y and x%5E2-4x-18+=+y , what is the product of
%28x-5%29%28x-7%29%28x%2B2%29%28x%2B3%29 in terms of y? 

Since x%5E2-3x-21+=+y and x%5E2-4x-18+=+y, then

x%5E2-3x-21+=+x%5E2-4x-18, since both equal y

simplifying:

-3x-21=-4x-18

x=3

So therefore

y+=x%5E2-3x-21+=+3%5E2-3%283%29-21=9-9-21=-21



So you're asking how to write 240 in terms of -21?

One way would be 240=%28-21%29%28-240%2F21%29+=+%28-21%29%2880%2F7%29

Somehow I think you're wanting something else, but I 
don't know what else.  Did you mistype something?

Edwin