SOLUTION: how do I solve (x^2-5x+5)^(x^2-9x+20)=1?

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Question 251178: how do I solve (x^2-5x+5)^(x^2-9x+20)=1?
Answer by stanbon(57282) About Me  (Show Source):
You can put this solution on YOUR website!
how do I solve (x^2-5x+5)^(x^2-9x+20)=1?
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That exponent must be zero.
x^2-9x+20 = 0
(x-5)(x-4) = 0
x = 5 or x = 4
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Cheers,
Stan H.