SOLUTION: 2) For the function y = x2 - 4x - 5, perform the following tasks: a) Put the function in the form y = a(x - h)2 + k. Answer: Show work in this space

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: 2) For the function y = x2 - 4x - 5, perform the following tasks: a) Put the function in the form y = a(x - h)2 + k. Answer: Show work in this space       Log On


   

Question 24896: 2) For the function y = x2 - 4x - 5, perform the following tasks:
a) Put the function in the form y = a(x - h)2 + k.
Answer:
Show work in this space











b) What is the line of symmetry?
Answer:



c) Graph the function using the equation in part a. Explain why it is not necessary to plot points to graph when using y = a (x - h)2 + k.
Show graph here.


Explanation of graphing.




d) In your own words, describe how this graph compares to the graph of y = x2?
Answer:




Answer by venugopalramana(3286) About Me  (Show Source):
You can put this solution on YOUR website!
Y=X^2-4X-5={(X-2)^2-4-5}=(X-2)^2-9
COMPARING WITH THE GIVEN EQN .
y=a%28x-h%29%5E2%2Bk,WE INFER THAT
A=1,H=2 AND K=-9....THE LINE OF SYMMETRY IS X-2=0 AS YOU WILL GET SAME VALUE OF Y WHETHER X-2=+4 SAY OR -4...NAMELY,Y=7.
COMPARISON WITH Y=X^2 IS SHOWN BELOW
+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+x%5E2-4x-5%2C+x%5E2%29+
YOU CAN SEE THAT LINE OF SYMMETRY IS X=0 HERE.
ALSO THE MINIMUM VALUE OR VERTEX AT 0,0 IN CASE OF Y=X^2,WHERE AS IT WAS AT (2,-9)
FOR THE GIVEN EQUATION