SOLUTION: Can you help solve this problem, I know that I'm missing something here.... f(x) = 1x^2 - 6x + 2 I just need the steps for the -6 when calculating the vertex - b/2a is confus

Algebra ->  Algebra  -> Quadratic Equations and Parabolas -> SOLUTION: Can you help solve this problem, I know that I'm missing something here.... f(x) = 1x^2 - 6x + 2 I just need the steps for the -6 when calculating the vertex - b/2a is confus      Log On

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Question 247840: Can you help solve this problem, I know that I'm missing something here....
f(x) = 1x^2 - 6x + 2
I just need the steps for the -6 when calculating the vertex - b/2a is confusing me.

Answer by stanbon(57387) About Me  (Show Source):
You can put this solution on YOUR website!
f(x) = 1x^2 - 6x + 2
I just need the steps for the -6 when calculating the vertex - b/2a is confusing me.
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You have a quadratic with a=1 , b=-6, and c= 2
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The vertex occurs when x = -b/(2a) = -(-6)/(2*1) = 6/2 = 3
f(3) = (3^2)-6*3+2 = 9-18+2 = -7
Vertex is at (3,-7)
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graph%28400%2C300%2C-10%2C10%2C-10%2C10%2Cx%5E2-6x%2B2%29
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Cheers,
Stan H.