SOLUTION: How do you solve {{{4/(m^2-7)=1}}}?

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Question 247659: How do you solve 4%2F%28m%5E2-7%29=1?
Answer by oberobic(2304) About Me  (Show Source):
You can put this solution on YOUR website!
4%2F%28m%5E2-7%29=1
.
Multiply both sides by %28m%5E2-7%29
4+=+m%5E2-7
.
Subtract 4 from both sides
0+=+m%5E2+-+11
or
m%5E2-11+=+0
.
Factor
%0D%0A%28m+%2B+sqrt%2811%29%29%28m+-+sqrt%2811%29%29+=+0%0D%0A
.
So, m+=+sqrt%2811%29%29 or m+=+-sqrt%2811%29%29