Question 242122: Find the smallest integral value of c for which the roots of 2x^2-8x+C=0 ARE imaginary.... please help and thanks Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Find the smallest integral value of c for which the roots of 2x^2-8x+C=0 ARE imaginary....
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The roots are imaginary when the discriminant is negative.
a = 2 ; b = -8 ; c = C
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discriminant = b^2-4ac = (-8)^2 - 4*2*C < 0
64 - 8C < 0
8C > 64
C > 8
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The roots are imaginary when C > 8.
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Cheers,
Stan H.
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