SOLUTION: solve the equation x squared minus 8x plus 25 = 0

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Question 241667: solve the equation x squared minus 8x plus 25 = 0
Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
Use the quadratic equation. This URL has a nice tool to do that
http://www.algebra.com/algebra/homework/quadratic/quadratic.solver

I used that to get this
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 1x%5E2%2B-8x%2B25+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%28-8%29%5E2-4%2A1%2A25=-36.

The discriminant -36 is less than zero. That means that there are no solutions among real numbers.

If you are a student of advanced school algebra and are aware about imaginary numbers, read on.


In the field of imaginary numbers, the square root of -36 is + or - sqrt%28+36%29+=+6.

The solution is x%5B12%5D+=+%28--8%2B-+i%2Asqrt%28+-36+%29%29%2F2%5C1+=++%28--8%2B-+i%2A6%29%2F2%5C1+

Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B-8%2Ax%2B25+%29