Question 230818: How so you solve this equation X^4+3x^3-8x-24=0?
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! Most classroom problems of this type have integer solutions.
The last term is 24, so try 1, 2, 3, 4, 6 until you find one (it could be + or minus).
2 is a solution, so divide by (x-2).
--> x^3 + 5x^2 + 10x + 12
-3 is a solution, divide by (3+3)
--> x^2 + 2x + 4
| Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc) |
Quadratic equation  (in our case  ) has the following solutons:
For these solutions to exist, the discriminant  should not be a negative number.
First, we need to compute the discriminant :  .
The discriminant -12 is less than zero. That means that there are no solutions among real numbers.
If you are a student of advanced school algebra and are aware about imaginary numbers, read on.
In the field of imaginary numbers, the square root of -12 is + or -  .
The solution is  , or
Here's your graph:
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