SOLUTION: last question. I have a problem figuring out how to graph the quadratic function. I need to understand how to do this can someone explain it to me please. thank u very much. th

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: last question. I have a problem figuring out how to graph the quadratic function. I need to understand how to do this can someone explain it to me please. thank u very much. th      Log On


   

Question 23010: last question. I have a problem figuring out how to graph the quadratic function. I need to understand how to do this can someone explain it to me please. thank u very much. the question says begin by graphing the standard quadratic function f(x)=x^2. The use transformation of this graph to graph the given function. g(x)=-1/2(x-3)^2-3 i am not understanding it. Help please
Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
Begin with f%28x%29+=+x%5E2
graph%28300%2C300%2C+-10%2C+10%2C+-10%2C10%2C+x%5E2+%29+

Next, what happens if you make that +%281%2F2%29%2Ax%5E2?
graph%28300%2C300%2C+-10%2C+10%2C+-10%2C10%2C+%281%2F2%29%2Ax%5E2+%29+
Answer: It opens the graph up to a broader shape!

Now, what happens if you make the function negative -%281%2F2%29%2Ax%5E2+
graph%28300%2C300%2C+-10%2C+10%2C+-10%2C10%2C+-%281%2F2%29%2Ax%5E2+%29+
Answer: It inverts the graph!

Now what happens if you make that -%281%2F2%29%2A%28x-3%29%5E2
graph%28300%2C300%2C+-10%2C+10%2C+-10%2C10%2C+-%281%2F2%29%2A%28x-3%29%5E2+%29+
Answer: It moves the graph 3 units to the right!

Finally, what happens if you subtract 3 from the previous function?
graph%28300%2C300%2C+-10%2C+10%2C+-10%2C10%2C+-%281%2F2%29%2A%28x-3%29%5E2+-3%29+
Answer: It moves the graph down three units.

Pretty neat, huh??

R^2 at SCC